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Add golden test that only one member-added message is shown for Bob

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Hocuri
2025-08-07 17:40:37 +02:00
parent a858709301
commit 8d89dcc65f
2 changed files with 13 additions and 6 deletions
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13
src/chat/chat_tests.rs
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@@ -3893,14 +3893,11 @@ async fn test_sync_broadcast() -> Result<()> {
.await .await
.unwrap(); .unwrap();
sync(alice0, alice1).await; // Sync QR code sync(alice0, alice1).await; // Sync QR code
tcm.exec_securejoin_qr_multi_device(bob, &[alice0, alice1], &qr) let bob_broadcast_id = tcm
.exec_securejoin_qr_multi_device(bob, &[alice0, alice1], &qr)
.await; .await;
// This also imports Bob's key from the vCard. let a1b_contact_id = alice1.add_or_lookup_contact_no_key(bob).await.id;
// Otherwise it is possible that second device
// does not have Bob's key as only the fingerprint
// is transferred in the sync message.
let a1b_contact_id = alice1.add_or_lookup_contact(bob).await.id;
assert_eq!( assert_eq!(
get_chat_contacts(alice1, a1_broadcast_id).await?, get_chat_contacts(alice1, a1_broadcast_id).await?,
vec![a1b_contact_id] vec![a1b_contact_id]
@@ -3923,6 +3920,10 @@ async fn test_sync_broadcast() -> Result<()> {
a0_broadcast_id.delete(alice0).await?; a0_broadcast_id.delete(alice0).await?;
sync(alice0, alice1).await; sync(alice0, alice1).await;
alice1.assert_no_chat(a1_broadcast_id).await; alice1.assert_no_chat(a1_broadcast_id).await;
bob.golden_test_chat(bob_broadcast_id, "test_sync_broadcast_bob")
.await;
Ok(()) Ok(())
} }

6
test-data/golden/test_sync_broadcast_bob Normal file
View File

@@ -0,0 +1,6 @@
InBroadcast#Chat#11: Channel [1 member(s)]
--------------------------------------------------------------------------------
Msg#11: info (Contact#Contact#Info): Establishing guaranteed end-to-end encryption, please wait… [NOTICED][INFO]
Msg#12🔒: (Contact#Contact#10): Member Me added by alice@example.org. [FRESH][INFO]
Msg#13🔒: (Contact#Contact#10): hi [FRESH]
--------------------------------------------------------------------------------